Match Coloum-I with Coloum-II and select the correct answer using codes given below the lists:
 

Coloum-I	Coloum-II
P) Boltmann constant	1)  $\left[M{L}^2{T}^{-1}\right]$
Q) Coefficient of viscosity	2) $\left[M{L}^{-1}{T}^{-1}\right]$
R) Plank constant	3) $\left[ML{T}^{-3}{K}^{-1}\right]$
S) Thermal conductivity	4) $\left[M{L}^2{T}^{-2}{K}^{-1}\right]$

 

 $P\to 4;Q\to 2;R\to 1;S\to 3$
(P):Using molecular kinetic energy relation, we have  $E=\frac{3}{2}kT$
Writing dimensions on the two sides, we have  $\left[M{L}^2{T}^{-2}\right]=\left[k\right]\left[K\right]\Rightarrow \left[k\right]=\left[M{L}^2{T}^{-2}{K}^{-1}\right]$
(Q): using Stokes rule, we have  $F=6\pi \eta rv$
Writing dimensions on the two sides, we have  $\left[ML{T}^{-2}\right]=\left[\eta \right]\left[L\right]\left[L{T}^{-1}\right]\Rightarrow \left[\eta \right]=\left[M{L}^{-1}{T}^{-1}\right]$
(R):Using relation of energy of a photon, we have  $E=hv$
Writing dimensions on the two sides, we have  $\left[M{L}^2{T}^{-2}\right]=\frac{\left[h\right]}{\left[T\right]}\Rightarrow \left[h\right]=\left[M{L}^2{T}^{-1}\right]$
(S): Using relation of steady state of heat conduction, we have  $\frac{dQ}{dt}=\frac{kA\left(\Delta T\right)}{\Delta x}$
 $\frac{\left[M{L}^2{T}^{-2}\right]}{\left[T\right]}=\frac{\left[k\right]\left[L^2\right]\left[K\right]}{\left[L\right]}$
 $\left[k\right]=\left[ML{T}^{-3}{K}^{-1}\right]$