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Match Column-I with Column –II and select the correct answer using the codes given below the lists :

List – I (position of the object)

List – II (magnification )
A
An object is placed at focus before a convex mirror
P
Magnification is - $\infty$
B
An object is placed at centre of curvature before a concave mirror
Q
Magnification is 0.5
C
An object is placed at focus before a concave mirror
R
magnification is +1
D
An object is placed at centre of curvature before a convex mirror
S
magnification is -1

T
magnification is 0.33

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$A \to q B \to p C \to s D \to r$

$A \to p B \to q C \to t D \to s$

$A \to q B \to s C \to p D \to t$

$A \to p B \to q C \to r D \to s$

answer is D.

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Detailed Solution

A-q: For $u = - f,$
$\frac{1}{v} + \frac{1}{- f} = \frac{1}{f}$
$∴ v = \frac{f}{2}$
And $M = - \frac{v}{u} = \frac{f / 2}{(- f)} = 0.5.$
$B - s : u = - 2 f, s o v = - 2 f$
$M = - \frac{v}{u} = - (\frac{- 2 f}{- 2 f}) = - 1$
C-P: In concave mirror , $u = - 2 f, v = - \infty$
   $M = - \frac{v}{u} = - \infty$
D-t: In convex mirror $u = - 2 f$
$S o, \frac{1}{v} + \frac{1}{- 2 f} = \frac{1}{f} \Rightarrow v = \frac{2 f}{3} .$

$N o w M = - \frac{v}{u} = \frac{1}{3} .$

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