Match Column I with Column II related to the figure given below and then select the appropriate option from the codes given below.
 

	Column I		Column II
A.	Figure represents	1.	Reduction
B.	${\mathrm{O}}_2\left(\mathrm{g}\right)+4{\mathrm{H}}^{+}\left(\mathrm{aq}\right)+4{\mathrm{e}}^{-}⟶2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$	2.	Corrosion of iron of atmosphere
C.	$\mathrm{Fe}\left(\mathrm{s}\right)⟶{\mathrm{Fe}}^{2+}\left(\mathrm{aq}\right)+2{\mathrm{e}}^{-}$	3.	Oxidation
D.	$2{\mathrm{Fe}}^{2+}\left(\mathrm{aq}\right)+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)+\frac{1}{2}{\mathrm{O}}_2⟶{\mathrm{Fe}}_2{\mathrm{O}}_3+4{\mathrm{H}}^{+}\left(\mathrm{aq}\right)$

Given figure represents the corrosion of iron in the atmosphere. Oxidation occurs at anode and reduction occurs at cathode
Cathode = $\begin{array}{l}{\mathrm{O}}_2\left(\mathrm{g}\right)+4{\mathrm{H}}^{+}\left(\mathrm{aq}\right)+4{\mathrm{e}}^{--}⟶2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right);\\ {\mathrm{E}}_{{\mathrm{H}}^{+}\left|{\mathrm{O}}_2\right|{\mathrm{H}}_2\mathrm{O}}^{\circ }=1.23\mathrm{V}\end{array}$
Anode = $2\mathrm{Fe}\left(\mathrm{s}\right)⟶2{\mathrm{Fe}}^{2+}\left(\mathrm{aq}\right)+4{\mathrm{e}}^{-};{\mathrm{E}}_{{\mathrm{Fe}}^{2+}/\mathrm{Fe}}^{\circ }=-0.44\mathrm{V}$
Overall reaction = $\begin{array}{l}2\mathrm{Fe}\left(\mathrm{s}\right)+{\mathrm{O}}_2\left(\mathrm{g}\right)+4{\mathrm{H}}^{+}\left(\mathrm{aq}\right)⟶2{\mathrm{Fe}}^{2+}\left(\mathrm{aq}\right)\\ +2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right);{\mathrm{E}}_{\mathrm{cell}}^{\circ }=1.67\mathrm{V}\end{array}$