Match List-I (Complexes) with List-II( Hybridization) of central atom and select the correct answer using the codes given below the lists:

List - I List - II
A. Ni(CO)₄ i. sp³
B. [Ni(CN)₄]^2- ii. dsp²
C. [Fe(CN)₆]^3- iii. sp³d²
D. [MnF₆]^4- iv. d²sp³
A B C D
1. i iii ii iv
2. i ii iv iii
3. ii iii i iv
4. i ii iv iii

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answer is D.

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Detailed Solution

$\begin{array}{l} [Ni (CO)_{4}] = {sp}^{3}; {[Ni (CN)_{4}]}^{2 -} = {dsp}^{2}; {[Fe (CN)_{6}]}^{4 -} = d^{2} {sp}^{3} \\ {[{MnF}_{6}]}^{4 -} = {sp}^{3} d^{2} \end{array}$

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