Match List-I with List-II and select the correct answer from the codes given below the lists:

	List-I          (reaction)		List-II (Product)
A)	${\text{CH}}_{\text{3}}-{\text{CH}}_{\text{2}}-\text{CH}={\text{CH}}_{\text{2}}\underset{{\text{(ii)\hspace{0.17em}NaBH}}_{\text{4}}}{\overset{{\text{(i)\hspace{0.17em}Hg(OAc)}}_{\text{2}}\text{/HOH}}{\to }}$	1)
B)	${\text{CH}}_{\text{3}}-{\text{CH}}_{\text{2}}-\text{CH}={\text{CH}}_{\text{2}}\underset{{\text{(ii)\hspace{0.17em}NaBH}}_{\text{4}}}{\overset{{\text{(i)\hspace{0.17em}Hg(OAc)}}_{\text{2}}{\text{/CH}}_3\text{OH}}{\to }}$	2)
C)	${\text{CH}}_{\text{3}}-{\text{CH}}_{\text{2}}-\text{CH}={\text{CH}}_{\text{2}}\underset{{\text{(ii)\hspace{0.17em}NaBH}}_{\text{4}}}{\overset{{\text{(i)\hspace{0.17em}Hg(OAc)}}_{\text{2}}{\text{/CH}}_3\text{COOH}}{\to }}$	3)
D)	${\text{CH}}_{\text{3}}-{\text{CH}}_{\text{2}}-\text{CH}={\text{CH}}_{\text{2}}\underset{{\text{(ii)\hspace{0.17em}NaBD}}_{\text{4}}}{\overset{{\text{(i)\hspace{0.17em}Hg(OAc)}}_{\text{2}}{\text{/H}}_2\text{O}}{\to }}$	4)

	A	B	C	D
a	2	4	3	1
b	4	2	3	1
c	2	4	1	3
d	2	4	3	1