Match List I with List II. List I(Conversion)List II(Numberof Faradayrequired)A)1 mol of H2O to O2I) 3FB)1 mol of MnO–4 to Mn2+II) 2FC)1.5 mol of Ca from molten CaCl2III) 1FD)1 mol of FeO to Fe2O3IV) 5FChoose the correct answer from the options given below. ABCD1IIIIIIIV2IIIIVIII3IIIVIIII4IIIIVIII

2H2O→O2(4F) H2O→12O2(2F) MnO4−→Mn+2 (5F) Ca1mole→Ca+2(2F) 1.5mole−(3F) 2FeO⇒Fe2O3(2F)

Match List I with List II. List I(Conversion)List II(Numberof Faradayrequired)A)1 mol of H2O to O2I) 3FB)1 mol of MnO–4 to Mn2+II) 2FC)1.5 mol of Ca from molten CaCl2III) 1FD)1 mol of FeO to Fe2O3IV) 5FChoose the correct answer from the options given below. ABCD1IIIIIIIV2IIIIVIII3IIIVIIII4IIIIVIII

2H2O→O2(4F) H2O→12O2(2F) MnO4−→Mn+2 (5F) Ca1mole→Ca+2(2F) 1.5mole−(3F) 2FeO⇒Fe2O3(2F)

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Match List I with List II.
List I(Conversion) List II(Number
of Faraday
required)
A) 1 mol of H₂O to O₂ I) 3F
B) 1 mol of MnO^–₄ to Mn²⁺ II) 2F
C) 1.5 mol of Ca from molten CaCl₂ III) 1F
D) 1 mol of FeO to Fe₂O₃ IV) 5F
Choose the correct answer from the options given below.
A B C D
1 II III I IV
2 III IV II I
3 II IV I III
4 III IV I II

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answer is C.

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Detailed Solution

$\begin{aligned} 2 H_{2} O \to O_{2} (4 F) \\ H_{2} O \to \frac{1}{2} O_{2} (2 F) \\ {MnO}_{4}^{-} \to {Mn}^{+ 2} (5 F) \\ \underset{1 mole}{Ca} \to {Ca}^{+ 2} (2 F) \\ 1.5 mole - (3 F) \\ 2 FeO \Rightarrow {Fe}_{2} O_{3} (2 F) \end{aligned}$

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