Match List I with List II

LIST I LIST II
A) $16 g of {CH}_{4} (g)$ I. Weights 28g
B) $1 g of H_{2} (g)$ II. 60.2 x 10²³
electrons
C) $1 mole of N_{2} (g)$ III. Weights 32g
D) $0.5 mol of {SO}_{2} (g)$ IV. Occupies 11.2L
volume at STP
Choose the correct answer from the options given below:
A B C D
1) II III IV I
2) II IV III I
3) I III II IV
4) II IV I III

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answer is D.

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Detailed Solution

1-II, 2-IV, 3-I, 4-III.

$16 g oƒ {CH}_{4} (g)$ =1 mole= 10N electrons.

$1 g oƒ H_{2} (g)$ = 0.5moles = 11.2L

$1 mole oƒ N_{2} (g)$ = 29140=28g

$0.5 mol oƒ {SO}_{2} (g)$ = 0.5 $\times$ 64=32g

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