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Match List-I with List-II:
List-I List-II
a) Boiling point order i) HF < HCl < HBr < HI
b) Melting point order ii) ${PH}_{3} < {AsH}_{3} < {NH}_{3} < {SbH}_{3}$
c) Acidic strength iii) ${TeO}_{2} < {SeO}_{2} < {SO}_{2}$
d) Reducing character iv) HCl<HBr<HF<HI
Choose the correct answer from the options given below

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a-ii, b-iv, c-i, d-iii

a-ii, b-iv, c-iv, d-i

a-iv, b-ii, c-iii, d-ii

a-iv, b-ii, c-i, d-iii

answer is D.

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Detailed Solution

Boiling point order--- ${PH}_{3} < {AsH}_{3} < {NH}_{3} < {SbH}_{3}$

Melting point order $HCl < H B r < HF < HI$

the reducing character of the dioxides decreases while their oxidising character increases.

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