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Match list–I with List–II

List–I List–II
a Charging cell e V = O
b Discharging cell f V = E
c Cell short circuited g V < E
d Cell in open circuit h V > E

	List–I		List–II
a	Charging cell	e	V = O
b	Discharging cell	f	V = E
c	Cell short circuited	g	V < E
d	Cell in open circuit	h	V > E

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a – g, b – h, c – e, d – f

a – g, b – e, c – h, d – f

a – f, b – g, c – h, d – e

a – h, b – g, c – e, d – f

answer is D.

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Detailed Solution

Charging cell : V = E + ir

Discharging cell : V = E − ir

Short circuit : There is no Potential Difference across battery so V = 0

In an open circuit there is no current in the circuit so : V = E

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