Match List-I with List-II: List-I Reaction List-IIProductA)CH4→Cu/523K,100 atmO2I)Ketone B)(CH3)2CH−CH= CH−CH3→O3/Zn+H2OII)Carboxylic acidC)(CH3)2C=C(CH3)2→∆KMnOIII)Alcohol D)CH3−CH3→O2/MnCH3COO2 IV)aldehyde ABCD1IVIIII2IIIIVIII3IIIIIIV4IVIVIIIChoose the correct answer from the options given below:

CH4→O2/Cu/523K,100 atmCH3OH CH3−CH3→O2/MnCH3COO2CH3−C||O−OH

Match List-I with List-II: List-I Reaction List-IIProductA)CH4→Cu/523K,100 atmO2I)Ketone B)(CH3)2CH−CH= CH−CH3→O3/Zn+H2OII)Carboxylic acidC)(CH3)2C=C(CH3)2→∆KMnOIII)Alcohol D)CH3−CH3→O2/MnCH3COO2 IV)aldehyde ABCD1IVIIII2IIIIVIII3IIIIIIV4IVIVIIIChoose the correct answer from the options given below:

CH4→O2/Cu/523K,100 atmCH3OH CH3−CH3→O2/MnCH3COO2CH3−C||O−OH

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Match List-I with List-II:
List-I
Reaction List-II
Product
A) $C H_{4} \to_{C u / 523 K, 100 a t m}^{O_{2}}$ I) Ketone
B) $\begin{array}{l} {(C H_{3})}_{2} C H - C H = \end{array} C H - C H_{3} \overset{O_{3} / Z n + H_{2} O}{\to}$ II) Carboxylic acid
C) ${(C H_{3})}_{2} C = C {(C H_{3})}_{2} \to_{∆}^{K M n O}$ III) Alcohol
D) $C H_{3} - C H_{3} \overset{O_{2} / M n {(C H_{3} C O O)}_{2}}{\to}$ IV) aldehyde
A B C D
1 IV I I II
2 III IV I II
3 III I I IV
4 IV IV I II
Choose the correct answer from the options given below:

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answer is B.

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Detailed Solution

$C H_{4} \overset{O_{2} / C u / 523 K, 100 a t m}{\to} C H_{3} O H$

$C H_{3} - C H_{3} \overset{O_{2} / M n {(C H_{3} C O O)}_{2}}{\to} C H_{3} - \overset{O}{\overset{| |}{C}} - O H$

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