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Match List-I with List-II.
List-I
(Transition metal ion) List-II
(Spin only magnetic moment (B.M.))
(A) Ti³⁺ (I) 3.87
(B) V²⁺ (II) 0.00
(C) Ni²⁺ (III) 1.73
(D) Sc³⁺ (IV) 2.84
Choose the correct answer from the options given below :

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(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

answer is B.

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Detailed Solution

$\begin{array}{lr} {Sc}^{+ 3} = 3 d^{\circ} ∴ μ_{spin} = 0 \\ V^{+ 2} = 3 d^{3} ∴ μ_{spin} = 3.87 B.M. \\ {Ni}^{+ 2} = 3 d^{8} ∴ μ_{spin} = 2.84 B.M. \\ {Ti}^{+ 3} = 3 d^{1} ∴ μ_{spin} = 1.73 B.M. \end{array}$

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