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Match List-I with List-II
List-I (Compound) List-II (Characteristics)
P) $B_{2} H_{6}$ 1) Half of the B atoms are bonded with nitrogen and adduct is formed
Q) $B_{2} H_{6} .2 N H_{3}$ 2) Inorganic graphite
R) $B_{3} N_{3} H_{6}$ 3) Inorganic benzene
S) ${(B N)}_{n}$ 4) Banana bond

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$P \to 1; Q \to 4; R \to 3; S \to 2$

$P \to 4; Q \to 1; R \to 2; S \to 3$

$P \to 1; Q \to 4; R \to 2; S \to 3$

$P \to 4; Q \to 1; R \to 3; S \to 2$

answer is A.

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Detailed Solution

$B_{2} H_{6}$ – Banana bond

$B_{2} H_{6} .2 N H_{3}$ – Half of the B atoms are bonded with nitrogen

$B_{3} N_{3} H_{6}$ – In organic benzene

${(B N)}_{n}$ – In organic graphite

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