Match of the following column: Column-I Column-II(a)Fe( III) >Fe( II) (p)Electronegativity(b)Al>Na(q)Basic character of their oxides(c)Cl>F(r)Electron gain enthalpy −ΔegH(d)N>C(s)Degree of hydration

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Match of the following column:

	Column-I		Column-II
(a)	$Fe (III) > Fe (II)$	(p)	Electronegativity
(b)	$Al > Na$	(q)	Basic character of their oxides
(c)	$Cl > F$	(r)	Electron gain enthalpy $(- Δ_{e g} H)$
(d)	$N > C$	(s)	Degree of hydration

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(a-r, q, r, s), [b-p, q, s), (c-r), (d-p)

(a-p, q, r, s), [b-p, r, s), (c-r), (d-p)

(a-p, q, r, s), [b-p, r, s), (c-s), (d-q)

(a-t, q, r, s), [b-p, r, s), (c-p), (d-p)

answer is B.

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Detailed Solution

Properties like Electronegativity, Basic character of their oxides, Electron gain enthalpy, Degree of hydration is greater for iron (III) then Fe (II).

While nitrogen has a higher electronegativity than carbon, clorine has a higher electron gain enthalpy than florine.

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