Match the bold substance in the reactions listed in column-I with their equivalent masseslisted in column-II (M = molecular mass of the substance in question) Column-I Column-IIA)FeC2O4 + Cr2O72- + H+ ProductsP)M/6B)Fe3O4 + MnO4- + H+ ProductsQ)M/2C)KHC2O4 + MnO4- + H+ ProductsR)MD)H2O2 + Cr2O72- + H+ ProductsS)M/3 ABCD1)QRSP2)PQRSSRPSQ4)SRQP

FeC2O4 : 3, Fe3O4(FeO.Fe2O3):1, KHC2O4 : 2, Cr2O72- : 6

Match the bold substance in the reactions listed in column-I with their equivalent masseslisted in column-II (M = molecular mass of the substance in question) Column-I Column-IIA)FeC2O4 + Cr2O72- + H+ ProductsP)M/6B)Fe3O4 + MnO4- + H+ ProductsQ)M/2C)KHC2O4 + MnO4- + H+ ProductsR)MD)H2O2 + Cr2O72- + H+ ProductsS)M/3 ABCD1)QRSP2)PQRSSRPSQ4)SRQP

FeC2O4 : 3, Fe3O4(FeO.Fe2O3):1, KHC2O4 : 2, Cr2O72- : 6

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Match the bold substance in the reactions listed in column-I with their equivalent masses
listed in column-II (M = molecular mass of the substance in question)

Column-I Column-II
A) FeC₂O₄ + Cr₂O₇^2- + H⁺ Products P) M/6
B) Fe₃O₄ + MnO₄^- + H⁺ Products Q) M/2
C) KHC₂O₄ + MnO₄^- + H⁺ Products R) M
D) H₂O₂ + Cr₂O₇²^- + H⁺ Products S) M/3
A B C D
1) Q R S P
2) P Q R S
S R P S Q
4) S R Q P

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answer is D.

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Detailed Solution

FeC₂O₄ : 3, Fe₃O₄(FeO.Fe₂O₃):1, KHC₂O₄ : 2, Cr₂O₇^2- : 6

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