Match the column Column-I Column-II ACl2+cold and dilute NaOH→ PDisproportionation take place BCl2+hot and conc.NaOH→ QChloride (Cl−) is producedC2NaNO3→500°CΔRChlorate ClO3− is produced DClO2+NaOH(aq)→SHypochlorite (OCl−) is produced TChlorite (ClO2−) is produced Uoxygen gas is liberated

(A) Cl2+cold and dilute 2NaOH→00CNaCl+NaOCl+H2O (B) Cl2+hot and cone. 6NaOH→Δ>500C5NaCl+NaClO3+3H2O (C) 2NaNO3→Δ2NaNO2+O2 (D) 2ClO2+H2O→HClO2+HClO3 +3 +5 HClO2+NaOH→NaClO2+H2O HClO3+NaOH→NaClO3+H2O

Match the column Column-I Column-II ACl2+cold and dilute NaOH→ PDisproportionation take place BCl2+hot and conc.NaOH→ QChloride (Cl−) is producedC2NaNO3→500°CΔRChlorate ClO3− is produced DClO2+NaOH(aq)→SHypochlorite (OCl−) is produced TChlorite (ClO2−) is produced Uoxygen gas is liberated

(A) Cl2+cold and dilute 2NaOH→00CNaCl+NaOCl+H2O (B) Cl2+hot and cone. 6NaOH→Δ>500C5NaCl+NaClO3+3H2O (C) 2NaNO3→Δ2NaNO2+O2 (D) 2ClO2+H2O→HClO2+HClO3 +3 +5 HClO2+NaOH→NaClO2+H2O HClO3+NaOH→NaClO3+H2O

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Match the column
Column-I Column-II
A $C l_{2} + c o l d_{} a n d_{} d i l u t e_{} N a O H \overset{}{\to}$ P Disproportionation take place
B $C l_{2} + h o t_{} a n d_{} c o n c . N a O H \to_{}^{}$ Q Chloride $(C l^{-})$ is produced
C $2 N a N O_{3} \to_{500 ° C}^{Δ}$ R Chlorate $(C l O_{3}^{-})$ is produced
D $C l O_{2} + N a O H (a q) \to$ S Hypochlorite $(O C l^{-})$ is produced
T Chlorite $(C l O_{2}^{-})$ is produced
U oxygen gas is liberated

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$(A \to P, Q, S), (B \to P, Q, R), (C \to U), (D \to P, R, T)$

$(A \to P, Q), (B \to Q, R), (C \to U), (D \to Q, R, T)$

$(A \to P, Q, S), (B \to P, Q, R), (C \to P, Q), (D \to P, R, T)$

$(A \to P, Q, S, T, U), (B \to P, R, T), (C \to Q, U), (D \to P, R, T)$

answer is A.

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Detailed Solution

(A) $C l_{2} + c o l d_{} a n d_{} d i l u t e_{} 2 N a O H \overset{0^{0} C}{\to} N a C l + N a O C l + H_{2} O$
(B) $C l_{2} + h o t_{} a n d_{} c o n e ._{} 6 N a O H \to_{Δ}^{> 50^{0} C} 5 N a C l + N a C l O_{3} + 3 H_{2} O$
(C) $2 N a N O_{3} \overset{Δ}{\to} 2 N a N O_{2} + O_{2}$
(D) $2 C l O_{2} + H_{2} O \to H C l O_{2} + H C l O_{3}$
+3 +5
$H C l O_{2} + N a O H \to N a C l O_{2} + H_{2} O$
$H C l O_{3} + N a O H \to N a C l O_{3} + H_{2} O$

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