Match the Column I with Column II and choose the correct option from the codes given below. Column I Column IIA.Mass of H2 produced when 0.5 mole of zinc reacts with excess of HCl.1.3.01×1023 moleculesB.Mass of all atoms of a compound with formula C70H22.2.6.023×1023 moleculesC.Number of molecules in 35.5 g of Cl23.1.43×10-21 gD.Number of molecules in 64 g of SO2.4.1g

(A) Zn + 2HCl → ZnCl2+H2 1 mole of Zn produces 2 g of H2 0.5 mole of Zn will produce 1 g of H2(B) C70H22 Molar mass = 862 Mass of atoms = 8626.023×1023 = 1.43×10-21 g(C) 70 g of Cl2 = 6.023×1023 molecules35.5 g of Cl2 = 3.01×1023 molecules(D) Molar mass of SO2 = 64 g = 1 mole 64 g of SO2 = 6.023×1023 molecules.

Match the Column I with Column II and choose the correct option from the codes given below. Column I Column IIA.Mass of H2 produced when 0.5 mole of zinc reacts with excess of HCl.1.3.01×1023 moleculesB.Mass of all atoms of a compound with formula C70H22.2.6.023×1023 moleculesC.Number of molecules in 35.5 g of Cl23.1.43×10-21 gD.Number of molecules in 64 g of SO2.4.1g

(A) Zn + 2HCl → ZnCl2+H2 1 mole of Zn produces 2 g of H2 0.5 mole of Zn will produce 1 g of H2(B) C70H22 Molar mass = 862 Mass of atoms = 8626.023×1023 = 1.43×10-21 g(C) 70 g of Cl2 = 6.023×1023 molecules35.5 g of Cl2 = 3.01×1023 molecules(D) Molar mass of SO2 = 64 g = 1 mole 64 g of SO2 = 6.023×1023 molecules.

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Match the Column I with Column II and choose the correct option from the codes given below.
Column I Column II
A. Mass of $H_{2}$ produced when 0.5 mole of zinc reacts with excess of HCl. 1. 3.01 $\times 10^{23} molecules$
B. Mass of all atoms of a compound with formula $C_{70} H_{22}$ . 2. $6.023 \times 10^{23} molecules$
C. Number of molecules in 35.5 g of ${Cl}_{2}$ 3. $1.43 \times 10^{- 21} g$
D. Number of molecules in 64 g of ${SO}_{2}$ . 4. 1g

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A-4 B-3 C-1 D-2

A -2 B -1 C- 4 D-3

A-4 B- 3 C -2 D-1

A-1 B-2 C-3 D-4

answer is C.

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Detailed Solution

(A) Zn + 2HCl $\to$ ${ZnCl}_{2} + H_{2}$

1 mole of Zn produces 2 g of $H_{2}$

$0.5 mole of Zn will produce 1 g of H_{2}$

(B) $C_{70} H_{22}$

Molar mass = 862

Mass of atoms = $\frac{862}{6.023 \times 10^{23}} = 1.43 \times 10^{- 21} g$

$35.5 g of {Cl}_{2} = 3.01 \times 10^{23} molecules$

(D) Molar mass of ${SO}_{2}$ = 64 g = 1 mole

$64 g of {SO}_{2} = 6.023 \times 10^{23} molecules .$

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