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Match the compounds in LIST-I with the observation in LIST-II, and choose the correct option.
LIST-I

LIST-II
(I) Chloroxylenol

(P)
Sodium fusion extract of the compound prepared by using sufficient amount of metallic sodium, on boiling with $F e S O_{4}$ , followed by acidification with conc. $H_{2} S O_{4}$ _,gives orange colour.

(II) Melamine

(Q)
Sodium fusion extract of the compound on treatment with sodium nitroprusside gives violet colour.

(III) Glucose

(R)
The compound decolourizes bromine water.

(IV) Methionine

(S)
Treating the compound with neutral $F e C l_{3}$ solution produces characteristic colour.

(T)
Treating the compound with nitrous acid at room temperature gives effervescence of $N_{2}$ .

(U)
The compound turns moist red litmus paper blue.

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$I \to U; I I \to S; I I I \to P; I V \to R$

$I \to U; I I \to T; I I I \to R; I V \to Q, T$

$I \to S; I I \to U; I I I \to R; I V \to Q$

$I \to S; I I \to T, U; I I I \to S; I V \to T$

answer is D.

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Detailed Solution

Chloroxylenol is a phenol
Melamine has - $N H_{2}$ groups
Glucose reduces bromine water.
Methionine is a sulphur containing amino acid.

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