Match the dimensional formula in COLUMN-I with the quantities in COLUMN-II
COLUMN-I COLUMN-II
A)    $M^{- 1} L^{- 3} T^{4} A^{2}$ p) Electric potential (V)
B)    $M L^{3} T^{- 3} A^{- 1}$ q) Electric field strength (E)
C)    $M L T^{- 3} A^{- 1}$ r) Electric flux ( $ϕ_{E}$ )
D) $M L^{2} T^{- 3} A^{- 1}$ s) Permittivity of vacuum ( $ε_{0}$ )

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a→s, b→r, c→q, d→p

a→s, b→p, c→r, d→q

a→r, b→p, c→s, d→q

a→s, b→s, c→r, d→q

answer is B.

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Detailed Solution

$| ε_{0} | = M^{- 1} L^{- 3} T^{4} A^{2} S o, A \to (s) [ϕ_{E}] = M L^{3} T^{- 3} A^{- 1} S o, B \to (r) | E | = [\frac{σ}{2 ε_{0}}] = M L T^{- 3} A^{- 1} s o, C \to (q, t) [V] = M L^{2} T^{- 3} A^{- 1} S o, D \to (p)$

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