Match the following : Column 1 - (Molecule) Column - 2 ( Hybridisation of central atom )

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$s p^{3}$

$s p^{3} d^{2}$

$s p^{3} d$

${XeO}_{2} F_{4}$

${CH}_{4}$

${XeF}_{2}$

$C_{2} H_{2}$

answer is A, B, C, D.

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Detailed Solution

In ${XeO}_{2} F_{4}$ , the central atom is ‘Xe’. In the second excited state there is six oribitals are available. One s-orbital three p-orbitals and two d-orbitals are hybridized to form six new $s p^{3} d^{2}$ hybrid orbitals.

In ${CH}_{4}$ x , the central atom is carbon. One s-orbital and three p-orbitals hybridized to form four new $s p^{3}$ hybrid orbitals.

In ${XeF}_{2}$ , the central atom is Xe. One s-orbital three p-orbitals and one d- orbitals are hybridized to form five new $s p^{3} d$ hybrid orbitals.

In $C_{2} H_{2}$ , the central atom is carbon. One s-orbital and one p-orbiral are hybridized to form two new sp hybrid orbitals.

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