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Q.

Match the following

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a

0π14sin2xdx==

,

0πx4sin2xdx=

,

0πsinx4sin2xdx=

,

0πxsinx4sin2xdx=

b

π263

,

π33

,

π243

,

π23

answer is A, B, C, D.

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Detailed Solution

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A-S,B-R,C-Q,D-P
A) 20π214sin2xdx;20π2sec2x4+3tan2xdx tanx=t 20dt4+(3t)2=2123tan13t20;π23
B) I0πx4sin2xdx;2I=π0πdx4sin2x=π223 I=π243
C) I=20π2sinx4sin2xdx=0π212sinx12+sinxdx =π33
D) 2I=π0πxsinx4sin2x=π233

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