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a

Number of arrangements of the letters of the word ENGINEER so that all vowels are together but all Es are not together is

,

Number of ways of arrangement the letters of the word ELEVEN so that no two vowels are together and no two consonants are together is k then 10 k equals

,

Number of ways of keeping 5 letters in 5 addressed envelopes such that no letter goes to its own envelope is p then p is divisible by

,

Number of 6 digits numbers greater than 123000 using 1,2,2,3,3,3 is

b

Question Image
,

22

,

5!

,

59

answer is C, A, D.

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Detailed Solution

A). In the word ENGINEER the vowels are E,E,E,I, consonants are N,N,G,R Required = (No. of arrangements in which E,E,E,I are together) – (No. of arrangemnets in which EEE are together when E,E,E,I are together)

=52×4352×2=60×(42)=120=5!

B). No.of arrangements of E,E,E and Consonants L,V,N alternately starting with E is 3 and starting with a
consonant is  3 K=Total no.of such arrangments = 3+3=12 

10K=120=5 ! 

C). P = No.of Derangements of 5 letters in 5 addresed envelops P=D5=44 

44 is divisible by 22 where 13 12C2=22

D). Using 1,2,2,3,3,3 numbers of 6 digits numbers that are starting with 123, 132,133 or 2 are greater than 123000. No.of such numbers =32+32+32+53+522=59

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