Match the following, and select the correct code.Column-IColumn -IIA)1.0 uP)4.98×10−23gB)Mass of 1.0 molecule of C2H6Q)1.66×10−23gC)1.0 mol of amuR)1.66×10−24gD)Mass of 10 protonsS)1.00 g

A1 u =1NAg=1.66×10−24g1 mole u =NA×1.66×10g−24=NA×1NAg=1gMass of 1 molecule of C2H6=30 u=4.98×10−24g =4.98×10−23gMass of 10 protons =10×mass of 1 proton =10×1u=1.66×10−23g

Match the following, and select the correct code.Column-IColumn -IIA)1.0 uP)4.98×10−23gB)Mass of 1.0 molecule of C2H6Q)1.66×10−23gC)1.0 mol of amuR)1.66×10−24gD)Mass of 10 protonsS)1.00 g

A1 u =1NAg=1.66×10−24g1 mole u =NA×1.66×10g−24=NA×1NAg=1gMass of 1 molecule of C2H6=30 u=4.98×10−24g =4.98×10−23gMass of 10 protons =10×mass of 1 proton =10×1u=1.66×10−23g

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Match the following, and select the correct code.
Column-I Column -II
A) 1.0 u P) $4.98 \times 10^{- 23} g$
B) Mass of 1.0 molecule of $C_{2} H_{6}$ Q) $1.66 \times 10^{- 23} g$
C) 1.0 mol of amu R) $1.66 \times 10^{- 24} g$
D) Mass of 10 protons S) 1.00 g

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answer is A.

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Detailed Solution

A
1 u $= \frac{1}{N_{A}} g = 1.66 \times 10^{- 24} g$
1 mole u $= N_{A} \times 1.66 \times 10_{g}^{- 24} = N_{A} \times \frac{1}{N_{A}} g = 1 g$
Mass of 1 molecule of $C_{2} H_{6} = 30 u = 4.98 \times 10^{- 24} g$
$= 4.98 \times 10^{- 23} g$
Mass of 10 protons $= 10 \times mass of 1 proton$
$\begin{array}{l} = 10 \times 1 u \\ = 1.66 \times 10^{- 23} g \end{array}$

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Column-I		Column -II
A)	1.0 u	P)	$4.98 \times 10^{- 23} g$
B)	Mass of 1.0 molecule of $C_{2} H_{6}$	Q)	$1.66 \times 10^{- 23} g$
C)	1.0 mol of amu	R)	$1.66 \times 10^{- 24} g$
D)	Mass of 10 protons	S)	1.00 g

Match the following, and select the correct code.Column-IColumn -IIA)1.0 uP)4.98×10−23gB)Mass of 1.0 molecule of C2H6Q)1.66×10−23gC)1.0 mol of amuR)1.66×10−24gD)Mass of 10 protonsS)1.00 g

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Match the following, and select the correct code.
Column-I Column -II
A) 1.0 u P) $4.98 \times 10^{- 23} g$
B) Mass of 1.0 molecule of $C_{2} H_{6}$ Q) $1.66 \times 10^{- 23} g$
C) 1.0 mol of amu R) $1.66 \times 10^{- 24} g$
D) Mass of 10 protons S) 1.00 g