Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

Match the following:

 Column I Column II
a)HF>HI>HBr>HClp)Reducing nature 
b)HI>HF>HBr>HClq)Ionic character 
c)HF>HCl>HBr>HIr)Melting point
d)HI>HBr>HCl>HFs)Boiling point

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

ap,bs,cr,dq

b

aq,bp,cr,ds

c

ar,bq,cp,ds

d

as,br,cq,dp

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Melting point: [HI(222)>HF(190)>HBr(185)>HCl(159)K]
Boiling point:  [HF(293)>HI(283)>HBr(206)>HCl(189)K]
Ionic character: Down the group, with the decrease in electronegativity of halogen, the dipole moment of the halogen acid hence the ionic character decreases.
Reducing nature: the reducing nature of a halogen acid depends upon the ease with it decomposes to give H2  and  X2 .

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon