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Q.

Match the following:

 Column-I Column-II
ANumber of triangles joining the vertices of the polygon having 35 diagonals isP1296
BMaximum number of point of intersection of six circles in the plane, isQ57
CNumber of straight lines joining any two of 12 points of which 5 are collinear, isR120
DNumber of rectangles in a 8×8 chess board, isS30

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a

(A)(S);(B)R;(C)(Q);(D)(P)

b

(A)(R);(B)(S);(C)(Q);(D)(P)

c

(A)(R);(B)(S);(C)(P);(D)(Q)

d

(A)(S);(B)(R);(C)(P);(D)(Q)

answer is B.

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Detailed Solution

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(A)We know that if polygon has n sides, then the total number of diagonals is  nC2n .
 nC2n=35n(n3)2=35
n23n70=0(n10)(n+7)=0 
 n=10
Now,with 10 vertices, number of triangles formed  =10C3=120
(B)Number of circles=6
  Maximum number of point of intersection  =2×6C2=30
(C) Number of straight lines with 12 points =12C2=66
Number of straight lines with 5 points =5C2=10
  Required number of straight lines  =6610+1=57
(D)A  8×8  chess board having 9 horizontal lines and 9 vertical lines.
 Required number of rectangles formed
 =9C2×9C2=1296

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