Match the following columns :

column-I	column-II
(a) 2 lone pairs are present	(p) ${\mathrm{XeF}}_5^{-}$
(b) Zero dipole moment	(q) ${\mathrm{NF}}_3$
(c) Planner	(r) ${\mathrm{ICl}}_3$
(d) All adjacent bond angles are equal	(s) ${\mathrm{XeF}}_4$

For ${\mathrm{XeF}}_5^{-}$,

No. of electron pair$=28+5+1=7$

Number of bond pair$=5.$ 

Number of lone pair $=2.$

Similarly in ${\mathrm{NF}}_3$, ${\mathrm{ICl}}_3$, there is two lone pair present.

Due to their equal and opposite magnitudes, the dipole moments connected to the lone pairs of ${\mathrm{XeF}}_5^{-}$ and ${\mathrm{NF}}_3$ will cancel each other out.
First three are triangular with two lone pairs.
Each and every molecule has an equal number of neighboring bonds with equal angles.