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Q.

Match the following columns.

 Column I (Distribution of particles ,A and B) Column II (Formula)
AA - At the corners and face centres
B - At the edge centres and body centre
1AB3
BA - At the corners
B - One on each body diagonal
2AB
CA - At the corners
B - At face centres
3AB4

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a

A - 1 ; B - 3 ; C - 2

b

A - 2 ; B - 3 ; C - 1

c

A - 2 ; B - 1 ; C - 3

d

A - 3 ; B - 2 ; C - 1

answer is B.

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Detailed Solution

(A). A atoms are at the corners and face centers, so number of A atoms =8×18+12×6=1+3=4
                                                                                                       corner atoms       Face center atoms
    B atoms are at the edge centers and body center, so number of B atoms per unit cell =12×14+1=3+1=4
     Ratio of A and B = 4 : 4 = 1:1 so formula is AB.
(B).A atoms are at the corners, so number of A atoms per unit cell =8×18=1 atom. 
   B atoms are at the body diagonals, so number of B atoms per unit cell = 4 x 1 = 4.
    Formula of molecule = AB4.
(C). When A atoms are at the corners and B atoms are at face centers, the formula is AB3.

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