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Q.

Match the following columns:

Column-IColumn-II (Oharacteristics)
(P) BrF2(1) d ,.2-orbital has participated in hybridisation of central atom
(Q) XeF5(2) sp3dhybridised central atom
(R) XeO2F2(3) hybridised central atom
(S) IOF5(4) See-saw geometry

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a

PQRS
4,2,41,31.3

b

PQRS
1,211,2,3,41

c

PQRS
2,32,41,2,41,4

d

PQRS
1,22,41,2,3,41

answer is A.

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Detailed Solution

XeF5 consists of two non-bonding electron pairs, one above and one below the plane. Five fluorine atoms are arranged in a pentagon shape.
In IOF5, there are six electron groups surrounding the central atom iodine. The molecule will have an octahedral molecular geometry because all of the electron groups are bonding pairs. That is, see saw.

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Match the following columns:Column-IColumn-II (Oharacteristics)(P) BrF2−(1) d ,.2-orbital has participated in hybridisation of central atom(Q) XeF5−(2) sp3d−hybridised central atom(R) XeO2F2(3) hybridised central atom(S) IOF5(4) See-saw geometry