Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

Match the following columns:

Column-IColumn-II
(a) B3N3H6(p) Planar
(b) XeO2F2(q) The central atom(s) is/are sp3d hybridised
(c) P5O155(r) Non-planar
(d) ICl3(s) The ratio of (σ:π) bonds is 4

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

(a-p, s); (b-q, r); (c-r, s); (d-r, q)

b

(a-s, p); (b-q, r); (c-r, q); (d-p, s)

c

(a-r, s); (b-q, r); (c-r, p); (d-q, s)

d

(a-q, r); (b-s, r); (c-r, q); (d-s, r)

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

A boron-nitrogen molecule (B3N3H6) having a six-membered ring and six pi electrons, borazole is also referred to as borazine. The compound is planar.
Trigonal bipyramidal geometry and nonplanar compound make up XeO2F2's structure.
Because iodine and chlorine have different electronegativities, the molecule ICl3 is polar and non-planar because its net dipole moment is not zero.

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon