Match the following List-I List-IIAIH3C−COOHBCH4→Mo2O3,ΔO2IICIIIH3C−CHODCH3−CH=CH−CH3→H+KMnO4IVHCHO

HC≡CH→H2OHg+, H+CH3CHO CH4→Mo2O3/heatO2HCHO CH32C=C(CH3)2→Zn, H2OO32CH3-CO-CH3 CH3-CH=CH-CH3→H+KMnO42CH3COOH

Match the following List-I List-IIAIH3C−COOHBCH4→Mo2O3,ΔO2IICIIIH3C−CHODCH3−CH=CH−CH3→H+KMnO4IVHCHO

HC≡CH→H2OHg+, H+CH3CHO CH4→Mo2O3/heatO2HCHO CH32C=C(CH3)2→Zn, H2OO32CH3-CO-CH3 CH3-CH=CH-CH3→H+KMnO42CH3COOH

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Match the following

List-I List-II
A
I $H_{3} C - COOH$
B ${CH}_{4} \to_{{Mo}_{2} O_{3}, Δ}^{O_{2}}$ II
C
III $H_{3} C - CHO$
D ${CH}_{3} - CH = CH - {CH}_{3} \to_{H^{+}}^{{KMnO}_{4}}$ IV $HCHO$

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A - III, B-IV, C-II, D-I

A - I, B - II, C - III, D - IV

A - III, B - II, C - IV, D - I

A - I, B-IV, C-III, D-II

answer is B.

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Detailed Solution

$HC \equiv CH \to_{H_{2} O}^{{Hg}^{+}, H^{+}} {CH}_{3} CHO {CH}_{4} \to_{{Mo}_{2} O_{3} / heat}^{O_{2}} HCHO {({CH}_{3})}_{2} C = C {({CH}_{3})}_{2} \to_{Zn, H_{2} O}^{O_{3}} 2 {CH}_{3} - CO - {CH}_{3} {CH}_{3} - CH = CH - {CH}_{3} \to_{H^{+}}^{{KMnO}_{4}} 2 {CH}_{3} COOH$

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	List-I		List-II
A		I	$H_{3} C - COOH$
B	${CH}_{4} \to_{{Mo}_{2} O_{3}, Δ}^{O_{2}}$	II
C		III	$H_{3} C - CHO$
D	${CH}_{3} - CH = CH - {CH}_{3} \to_{H^{+}}^{{KMnO}_{4}}$	IV	$HCHO$

Match the following List-I List-IIAIH3C−COOHBCH4→Mo2O3,ΔO2IICIIIH3C−CHODCH3−CH=CH−CH3→H+KMnO4IVHCHO

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Match the following

List-I List-II
A
I $H_{3} C - COOH$
B ${CH}_{4} \to_{{Mo}_{2} O_{3}, Δ}^{O_{2}}$ II
C
III $H_{3} C - CHO$
D ${CH}_{3} - CH = CH - {CH}_{3} \to_{H^{+}}^{{KMnO}_{4}}$ IV $HCHO$