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Q.

Match the following:

 List I        List II
I)Density  1.25  g/LP)18 g water at  25C  o
II)22.4 L of volumeQ)1gH2(g)  at  0C  o , 1 bar
III)6.022×1023  moleculesR)16g  O2(g) at   0C  o , 1 bar
IV)11.35  L volumeS)1 mol  N2(g)  at  0C  o , 1 atm
  T)1 mol C2H4(g)  at   0C  o , 1 atm

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a

(I-S, T), (II-Q, R), (III-S, T), (IV-P, R)

b

(I-Q, R), (II-S, T), (III-P), (IV-Q, T )

c

(I-S, T), (II-S, T), (III-P, S, T), (IV-Q, R)

d

(I-T), (II-S), (III-P, S), (IV-R, S)

answer is C.

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Detailed Solution

18  g  H2O=1  mol=6.022×1023  molecules
1  g  H2(0.5  mol)  at  0C  o  and  1 bar  =22.7/2=11.35  L
16  g  O2(0.5mol)   at  0C  o  and 1 bar  =22.7/2=11.35  L
1 mol  N2  at  0  oC  and 1 atm = 22.4 L, and 28/22.4 = 1.25 g/L (density)
1 mol C2H4(28g)   at  0C  o  and 1 atm = 22.4L, and 28/22.4=1.25 g/L (density)

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