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Q.

Match the following List-I with List -II

List-I

List-II

(I)

If f:RR is a differentiable function with property that  limxf(x)=7 and if limxxf'(x) exists, then this limit is equal to 

P

1

(II)

Let f and g be n-times continuously differentiable function in a neighbourhood of a point ‘a’ such that  f(a)=g(a)=ln2f1(a)=g1(a),......,f(n1)(a)=g(n1)(a)  and  fn(a)gn(a), then  limxaef(x)eg(x)f(x)g(x) is

Q

3

(III)

Let f:[a,b]R be a function continuous on [a,b] and differentiable on (a,b) if there exist C(a,b) such that f(b)f(c)f(c)f(a)<0, then there always exist  μ(a,b), such that f1(μ) is equal to

R

5

(IV)

Let a and b be positive real numbers, then abexaebxxdx is

S

7

 

 

T

2

 

 

U

0

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a

IS,IIS,IIIQ,IVP

b

IU,IIS,IIIQ,IVR

c

IS,IIP,IIIP,IVQ

d

IU,IIT,IIIU,IVU

answer is D.

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Detailed Solution

detailed_solution_thumbnail

(P) is let  l=limxf(x)=limxxf(x)x=limxxf'(x)+f(x)1=limxxf'(x)+l
   limxxf'(x)=0
Q)  limxef(x)eg(x)f(x)g(x);limxeg(x)[ef(x)g(x)1]f(x)g(x) use  L.H  rule
 eg(a)e(f(x)g(1))(f1(x)g1(x))(f1(x)g1(x));eg(a)=eln2=2
R) Replacing f by f if necessary, we may assume f(b)> f(c) hence f(a)> f(c)
So, μ be an absolute minimum of f on [a,b] which exists became the function is continuous then μ(a,b) and therefore f1(μ)=0
S) I=abexaebxxdx  put  t=abxx=abt  we  have  dx=abt2dt
I=baeabatebxabt(abt2)dt;I=baebtetat(dt)=abebtetat.dt=1  I=0

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