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Match the following logic circuits given in column I with the output equation in column II.( $\bar{A} a n d \bar{B}$ are inverted versions of A and B respectively)

Column I Column II
A
P $Y = \bar{A} + \bar{B}$
B
Q $Y = \bar{A} . \bar{B}$
C
R $Y = A . B$
D
S $Y = A + B$

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$A \to R, B \to S C \to P, D \to Q$

$A \to S, B \to R, C \to P, D \to Q$

$A \to P, B \to Q, C \to R, D \to S$

$A \to S, B \to P, C \to Q, D \to R$

answer is A.

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Detailed Solution

$(A) A B = A B A N D g a t e$ (R)

$(B) (A + B) = A + B O R g a t e$ (S)

$(C) A B = A + B$ (P)

$(D) A + B = A B$ (Q)

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