Match the following two columns corresponding to single refraction from plane surface. In all cases shown in Column I, $μ_{1} > μ_{2} .$
Column I Column II
a)
p) Image distance greater than x from plane surface
b)
q) Image distance less than x from plane surface
c)
r) Real image
d)
s) Virtual image

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a-ps; b-qs; b-qr; d-pr

a-pr; b-ps; c-ps; d-qs

a-qs; b-qr; c-ps; d-pr

a-qr; b-qs; c-pr; d-ps

answer is A.

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Detailed Solution

(a) and (b)
$v = \frac{μ_{2}}{μ_{1}} μ \Rightarrow | v | < | u |$ as $μ_{1} > μ_{2}$
i.e $v and u$ are of same sign.
Or they are on same side of plane surface. From plane surface, if object is real, image is virtual and vice-versa.

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