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Q.

Match the following 

 COLUMN - I COLUMN - II
A)If z1, z2, z3 are vertices
of an equilateral triangle then
p)z1z22+3z3z22=0
B)If z1, z2, z3 are vertices of A, B, C of an isosceles right angled triangle 
respectively  with right angle at C, 
then 
q)z2z32=3z1z2z3z1
C)If z1, z2, z3 are vertices of A, B, C  of an isosceles triangle respectively and angles B & C are
each equal to π6then
 
r)z1z22=2z1z3z3z2
D)If z1, z2, z3 are vertices of A, B, C respectively
of a triangle ABC in whichA=π6,B=π2, C=π3, then 
s)z1z22+z2z32+z3z12=0
 (A)(B)(C)(D)
1)srqp
2)rqsq
3)psrr
4)qpps

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a

2

b

1

c

3

d

4

answer is A.

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Detailed Solution

a) 

Question Image

BA¯=BC¯e3;z1z2=z3z2eiπ3………(1)
CA¯=CB¯e3z1z3=z2z3e3…..(2)
From (1) & (2) z2z1z3z2=z3z2z3z1
z12=z1z2as
b) CA¯=CB¯e2z1z3=z2z3(i)…..(1)
BA¯=2BC¯e4z1z22=2Z3Z22(i)z1z22=2z3z22z3+z1z2+z3=2z3z2z1z3br

Question Image

c) BA¯=13BC¯e6,CA¯=13BC¯e6
BC¯2=3BA¯CA¯z2z32=3z3z1z2z13z1z2z3z1
 

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d) BA¯=3BC¯e2
Squaring we get 
z1z22=3z3z22(1)dp

Question Image
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