Match the following:
Column – I
Column – II
A) Avogadro number 1) Weighs 32 g
B) 18g of water 2) N
C) 22.4 litres of oxygen at STP 3) 1/12^th of the mass of C-12 atom
D) 1 a.m.u 4) U
E) Unified mass 5) 1 mole of water

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A-2, B-5, C-1, D-3, E-4

A-2, B-5, C-3, D-1, E-4

A-2, B-5, C-3, D-4, E-1

A-2, B-5, C-4, D-3, E-1

answer is D.

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Detailed Solution

Mole = gram molecular weight of the substance

1 mole of any gas occupies 22.4 lit or gram molecular weight of substance.

1 a.m.u is equal to the quantity of 1/12th of the mass of C-12 atom.

Avogardo’s number is indicated by $N_{A}$ .

At STP 22.4 L of oxygen means 1 mol of oxygen that is equal to 32 g.

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