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Q.

Match the following:

Column – I

Column – II

A) Avogadro number1) Weighs 32 g
B) 18g of water2) N
C) 22.4 litres of oxygen at STP3) 1/12th of the mass of C-12 atom
D) 1 a.m.u4) U
E) Unified mass5) 1 mole of water

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a

A-2,  B-5,  C-1,  D-3,  E-4

b

A-2,  B-5,  C-3,  D-1,  E-4

c

A-2,  B-5,  C-3,  D-4,  E-1

d

A-2,  B-5,  C-4,  D-3,  E-1

answer is D.

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Detailed Solution

 Mole = gram molecular weight of the substance

1 mole of any gas occupies 22.4 lit or gram molecular weight of substance.

1 a.m.u is equal to the quantity of 1/12th of the mass of C-12 atom.

Avogardo’s number is indicated by NA.

At STP 22.4 L of oxygen means 1 mol of oxygen that is equal to 32 g.

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