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Match the following
List-I(Colour) List-II(Elements)
a. Prussian blue i.   ${[F e {(C N)}_{5} N O S]}^{4 -}$
b. Violet ii.   $F e_{4} {[F e {(C N)}_{6}]}_{3}$
c. Blood red iii.   ${[F e (S C N)]}^{2 +}$
d. white iv.   $A g C l$
v.   $N a_{4} [F e {(C N)}_{6}]$

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A-ii, B-i, C-v, D-iii

A-iv, B-i, C-iii, D-v

A-i, B-iii, C-ii, D-iv

A-ii, B-i, C-iii, D-iv

answer is D.

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Detailed Solution

${[F e {(C N)}_{6}]}^{4 -} + 4 F e^{+ 3} \to \underset{(P e r s s i a n B l u e)}{F e_{4} {[F e {(C N)}_{6}]}_{3}}$

$S^{- 2} + {[F e {(C N)}_{5} N O]}^{- 2} \to \underset{(V i o l e t)}{{[F e {(C N)}_{5} N O S]}^{- 4}}$

$F e^{+ 3} + S C N^{-} \to \underset{(B l o o d r e d)}{{[F e (S C N)]}^{2 +}}$

$N a C l + A g N O_{3} \to \underset{(w h i t e)}{A g C l + N a N O_{3}}$

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List-I(Colour)	List-II(Elements)
a. Prussian blue	i. ${[F e {(C N)}_{5} N O S]}^{4 -}$
b. Violet	ii. $F e_{4} {[F e {(C N)}_{6}]}_{3}$
c. Blood red	iii. ${[F e (S C N)]}^{2 +}$
d. white	iv. $A g C l$
	v. $N a_{4} [F e {(C N)}_{6}]$

Match the followingList-I(Colour)List-II(Elements)a. Prussian bluei. [Fe(CN)5NOS]4−b. Violetii. Fe4[Fe(CN)6]3c. Blood rediii. [Fe(SCN)]2+d. whiteiv. AgCl v. Na4[Fe(CN)6]