Match the following 

List I	List II
(A)  Aqueous solution of  ${\mathrm{Na}}_2{\mathrm{SO}}_4$	(I) Acidic due to cationic hydrolysis
(B) ${\mathrm{CH}}_3\mathrm{COONa}+{\mathrm{CH}}_3\mathrm{COOH}$	(II) Basic solution
(C) ${\mathrm{AlCl}}_3$	(III) Neutral solution
(D) Aqueous solution of  ${\mathrm{CH}}_3\mathrm{COONa}$	(IV) Acidic due to buffer action
	(V) Basic solution due to buffer action

            The correct match is 

(A) ${\mathrm{Na}}_2{\mathrm{SO}}_4$ ionizes as ${\mathrm{Na}}^{+}$ and ${\mathrm{SO}}_4^{2-}$and there is no hydrolysis.  So neutral (III).

(B) Mixture of weak acid and its salt with a strong base.  So it is acidic buffer (IV).

(C) ${\mathrm{AlCl}}_3\to {\mathrm{Al}}^{3+}+3{\mathrm{Cl}}^{-}$

${\mathrm{Al}}^{3+}+3{\mathrm{H}}_2\mathrm{O}\rightleftharpoons \mathrm{Al}{\left(\mathrm{OH}\right)}_3+3{\mathrm{H}}^{+}$

       So acidic due to cationic hydrolysis (I)

(D) ${\mathrm{CH}}_3\mathrm{COONa}\to {\mathrm{CH}}_3\mathrm{COOH}+\mathrm{Na}$

${\mathrm{CH}}_3{\mathrm{COO}}^{-}+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{OH}}^{-}$ so basic due to anionic hydrolysis (II)