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Q.

Match the following

 Molecules Empirical formula
A)Glucosea)BNH2
B)Oxalic acidb)CH2O
C)Inorganic Benzenec)CH
D)Oxygenated waterd)CHO2
  e)HO

The correct match is

 ABCD
1)cebd
2)bdae
3)acbd
4)dbac

see full answer

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a

2

b

1

c

3

d

4

answer is B.

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Detailed Solution

The correct match for the question is option 2:

  • Glucose: The molecular formula of glucose is C6H12O6. The empirical formula of glucose is CH2O. This is the empirical formula of glucose, derived by simplifying the molecular formula.
  • Oxalic Acid: The molecular formula of oxalic acid is C2H2O4. The empirical formula of oxalic acid is CHO2, as it is the simplest ratio of the elements in the molecule.
  • Inorganic Benzene (Borazole): The molecular formula of inorganic benzene, also known as Borazole, is B3N3H6. The empirical formula of Borazole is BNH2, which represents the simplest ratio of boron, nitrogen, and hydrogen atoms in the compound.
  • Oxygenated Water (Hydrogen Peroxide): The molecular formula of hydrogen peroxide is H2O2. The empirical formula of hydrogen peroxide is HO, representing the simplest ratio of hydrogen and oxygen atoms.

Why the Empirical Formula of Glucose is CH2O

The empirical formula of glucose is CH2O because it represents the simplest whole-number ratio of atoms in glucose. The molecular formula of glucose (C6H12O6) shows that the number of carbon, hydrogen, and oxygen atoms are all divisible by 6. Therefore, dividing each by 6 gives the empirical formula, CH2O, which is the simplest form of the molecular structure.

Empirical Formula of Glucose: CH2O

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