Match the following

	Molecules		Empirical formula
A)	Glucose	a)	BNH2
B)	Oxalic acid	b)	CH2O
C)	Inorganic Benzene	c)	CH
D)	Oxygenated water	d)	CHO2
		e)	HO

The correct match is

	A	B	C	D
1)	c	e	b	d
2)	b	d	a	e
3)	a	c	b	d
4)	d	b	a	c

The correct match for the question is option 2:

• Glucose: The molecular formula of glucose is C₆H₁₂O₆. The empirical formula of glucose is C_H2O. This is the empirical formula of glucose, derived by simplifying the molecular formula.
• Oxalic Acid: The molecular formula of oxalic acid is C₂H₂O₄. The empirical formula of oxalic acid is CHO₂, as it is the simplest ratio of the elements in the molecule.
• Inorganic Benzene (Borazole): The molecular formula of inorganic benzene, also known as Borazole, is B₃N₃H₆. The empirical formula of Borazole is BNH₂, which represents the simplest ratio of boron, nitrogen, and hydrogen atoms in the compound.
• Oxygenated Water (Hydrogen Peroxide): The molecular formula of hydrogen peroxide is H₂O₂. The empirical formula of hydrogen peroxide is HO, representing the simplest ratio of hydrogen and oxygen atoms.

Why the Empirical Formula of Glucose is C_H2O

The empirical formula of glucose is C_H2O because it represents the simplest whole-number ratio of atoms in glucose. The molecular formula of glucose (C₆H₁₂O₆) shows that the number of carbon, hydrogen, and oxygen atoms are all divisible by 6. Therefore, dividing each by 6 gives the empirical formula, C_H2O, which is the simplest form of the molecular structure.

Empirical Formula of Glucose: C_H2O