Match the items of Column I and Column II on the basis of data given below.
        $\begin{array}{r}{\mathrm{E}}_{{\mathrm{F}}_2/{\mathrm{F}}^{-}}^{\circ }=2.87\mathrm{V},{\mathrm{E}}_{{\mathrm{Li}}^{+}/\mathrm{Li}}^{\circ }=-3.5\mathrm{V},\\ {\mathrm{E}}_{{\mathrm{Au}}^{3+}/\mathrm{Au}}^{\circ }=1.4\mathrm{V},{\mathrm{E}}_{{\mathrm{Br}}_2/{\mathrm{Br}}^{-}}^{\circ }=1.09\mathrm{V}\end{array}$
 

	Column I		Column II
A	F2	1.	Metal is the strongest reducing agent.
B	Li	2.	Metal ion which is the weakest oxidising agent.
C	Au3+	3.	Non-metal which is the best oxidising agent.
D	Br-	4.	Unreactive metal.
E	Au	5.	Anion that can be oxidised by Au3+.
F	Li+	6.	Anion which is the weakest reducing agent.
G	F-	7.	Metal ion which is an oxidising agent.

$\begin{array}{l}\text{ A. }\to \text{ (3) }\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\text{ B. }\to \text{ (1) }\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\text{ C. }\to \text{ (7) D. }\to \left(5\right) \\ \text{ E. }\to \text{ (4) }\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\text{ F. }\to \text{ (2) }\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\text{ G. }\to \left(6\right)\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\end{array}$
A. F₂ it a non-metal and best oxidising agent because SRP of F₂ is + 2.87 V.
B. Li is a metal and strongest reducing agent because SRP of Li is - 3.05 V.
C. Au³⁺ is a metal ion which is an oxidising agent as SRP of Au³⁺ is +1.40 V.
D. Br^- is an anion that can be oxidised by Au³⁺ as Au³⁺ (E^o = 1.40) is greater than Br^- (E^o = 1.09 V).
E. Au is an un reactive metal.
F. Li⁺ is a metal ion having least value of SRP (-3.05 V), hence it is the weakest oxidising agent.
G. F^- is an anion which is the weakest reducing agent as F^- / F₂ has low oxidation potential (-2.87 V).