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Match the list-I with List-II and select the answer using the codes give below the lists
List-I (Anionic species) List-II (ore)
a) Carbonate 1 ) Siderite
b) Sulphide 2) Malachite
c) Hydroxide 3) Bauxite
d) Oxide 4) Calamine
5) Argentite

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a-2,4,5,b-1;c-2,5,d-3

a-2,1,3;b-4;c-3,4;d-5

a-1,2,4;b-5;c-2,3,d-3

a-2,3,4;b-5;c-3,4;d-1

answer is A.

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Detailed Solution

Siderite - $F e C O_{3}$

calamine - $Z n C O_{3}$

Malachite - $C u C O_{3} C u {(O H)}_{2}$

Argentite - $A g_{2} S$

Bauxite - Al₂O₃

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