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Q.

Match the process given in column-I with the expression of thermodynamic quantities given in column-II

 Column-I Column-II
AHeating of an ideal gas at constant pressurePΔH=nCp,mΔT0
BCompression of liquid at constant temperatureQ          ΔU = 0
CReversible process for an ideal gas at constant temperatureR    ΔG = VΔP
DAdiabatic free expansion of an Ideal gas S    ΔG=nRTln(P2P1)

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a

A-P ; B-R; C-Q,S; D-Q

b

A-S ; B-P; C-Q; D-R

c

A-Q,S ; B-P; C-S; D-R

d

A-R ; B-S; C-P; D-Q

answer is A.

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Detailed Solution

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a) Heating ΔT>0ΔH>0

b) ΔG=VΔpSΔT

at const Temp ΔT=C

ΔG=VΔρ0

ΔG=VΔρ

Liquid ΔU0

c) Const Temp ΔT=0

Ideal gas ΔU=0

dg=Vdp=nRTρdpΔG=nRTlnP2/P1

d) adiabatic q = 0
Free expansion w = 0
q+w=ΔU=0+0=0

q=0,w=0,ΔU=0

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