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Match the solid in Column-I with its characteristic in Column-II.
Column-I (Solid) Column-II (Characteristic)
A) NaCl p) Body centred cubic
B) CsCl q) Packing fraction = 0.68
C) Na r) Packing fraction $= \frac{2 π}{3} \frac{(r_{+}^{3} + r_{-}^{3})}{{(r_{+} + r_{-})}^{3}}$
D) TiCl s) Packing fraction $\frac{\sqrt{3}}{2} π \frac{(r_{+}^{3} + r_{-}^{3})}{{(r_{+} + r_{-})}^{3}}$

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Detailed Solution

For $NaCl = \frac{4 \times \frac{4}{3} π {(r^{+} + r^{-})}^{3}}{2^{3} \times {(r^{+} + r^{-})}^{3}} = \frac{2}{3} \frac{π {(r^{+} + r^{-})}^{3}}{{(r^{+} + r^{-})}^{3}}$

$= \frac{4}{3} \frac{π (r^{+} + r^{-})}{{(\frac{2}{3})}^{3} {(r^{+} + r^{-})}^{3}} = \frac{\sqrt{3}}{2} \frac{π {(r^{+} + r^{-})}^{3}}{{(r^{+} + r^{-})}^{3}}$
Na – BCC, P.F = 0.68
$TiCl - BCC, P . F = \frac{\sqrt{3} π}{2} \frac{{(r^{+} + r^{-})}^{3}}{{(r^{+} + r^{-})}^{3}}$

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