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Q.

Match the species in Column I with the type of hybrid orbitals in Column-II.

  
(a) SF4(i) sp3d2
(b) IF5(ii) d2sp3
(c) BeCl2(iii) sp3d
(d) NH4+(iv) sp3
 (v) sp

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a

(a)-(iv), (b)-(iii), (c)-(v), (d)-(i) 

b

(a)-(iii), (b)-(i), (c)-(v), (d)-(iv)

c

(a)-(i), (b)-(ii), (c)-(v), (d)-(iii)

d

(a)-(ii), (b)-(i), (c)-(iv), (d)-(v)

answer is D.

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Detailed Solution

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SF4 has sp3d hybridization. IF5 has sp3d2 hybridization. BeCl3 has sp hybridization. NH4+ has sp3 hybridization.

(a)-(iii), (b)-(i), (c)-(v), (d)-(iv)

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