Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Match the statements of Column I with values of Column II.
 

 COLUMN - I COLUMN - II
a.The least positive integral values of λ for which
 (λ2)x2+8x+(λ+4)>0 for all real x is
p.3
b.The equation x2+2a2+1x+a214a+48=0 possesses 
 roots of opposite signs then x value of ‘a’ can be
q.5
c.If the equation ax2+2bx+4c=16 has  no real roots 
and a+c>b+4 then integral value of c can be equal to
r.7
d.If N be the number of solution of the equation 
x2x6=x+2 then the value of N is
s.12
  t.20

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

answer is , , , .

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

A) λ>2,644(λ2)(λ+4)<0λ<6 or λ>4
The least positive integral value of λ is 5
B) Roots are of opposite signs a214a+48<0
(a=6)(a8)<0 so a can be 7
The equation is x2+100x1=0
discriminant = =D=1002+4>0 .Roots are real
C) Let f(x)=ax2+2bx+4c16 ,Clearly f(2)=4a4b+4c16
=4(ab+c4)>0=f(x)>0,xR,f(0)>04c16>0c>4
D) x2x6=x+2|(x3)(x+2)|=x+2
|x3||x+2|=x+2
(x3)(x+2)=x+2,x<2(x3)(x+2)=x+2,2x<3(x3)(x+2)=x+2,x>3
x=4,x<2x=2,22x<3x=4,x<3, Hence, x=2,2,4 N=3

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring