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Q.

Maximise Z=x+2y
subject to the constraints
x+2y1002xy02x+y200x,y0
Solve the above LPP graphically.

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Detailed Solution

Minimize & Maximize z=x+2y
Subject to,
x+2y1002xy02x+y200x,y0
x+2y∣≥100

x0100
y500

2xy0
 

x050
y0100

2x+y200
 

y1000
x0200

∴Z=400 is maximum at (0,200)
Also,
Z is minimum at two points (0,50) & (20,40)
∴Z=100 is minimum at all points joining (0,50) & (20,40)
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