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Maximum height reached by a rocket fired with a speed equal to 50% of the escape velocity from earth’s surface is:

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R/3

16R/g

R/8

R/2

answer is C.

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Detailed Solution

Escape velocity causes KE of $\frac{G M m}{R}$ . Half of such speed causes KE of $\frac{G M m}{4 R}$ . Conserving total energy,

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