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Maximum kinetic energy of a photoelectron is $E$ when the wavelength of incident light is $λ$ . If energy becomes four times when wavelength is reduced to one-third, then work-function of the metal is

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$\frac{h c}{2 λ}$

$\frac{3 h c}{λ}$

$\frac{h c}{λ}$

$\frac{h c}{3 λ}$

answer is B.

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Detailed Solution

$∵ E = \frac{h c}{λ} - W . . . (i) 4 E = \frac{h c}{\frac{λ}{3}} - W . . . (i i)$
Solving these equations, we get
$W = \frac{h c}{3 λ}$

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