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Q.

Maximum kinetic energy of photoelectron emitted from the surface of work function $ϕ$ due to incidence of light
of frequency ‘ $v$ ’ is E. If the frequency of incident light is tripled, then maximum kinetic energy of emitted photon will be

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a

$3 E - ϕ$

b

$3 E + 2 ϕ$

c

$3 E + ϕ$

d

$3 E$

answer is D.

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Detailed Solution

$E = h v - ϕ$

$\begin{array}{l} E^{1} = 3 h v - ϕ \\ = 3 (h v - ϕ) + 2 ϕ \\ = 3 E + 2 ϕ \end{array}$

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Maximum kinetic energy of photoelectron emitted from the surface of work function ϕ due to incidence of lightof frequency ‘v’ is E. If the frequency of incident light is tripled, then maximum kinetic energy of emitted photon will be