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Q.

Maximum speed of a particle in simple harmonic motion is V_max. For 1 oscillations average speed of a particle in SHM is equal to

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a

2V_max / $π$

b

V_max / 2

c

$π$ V_max /2

d

V_max / $π$

answer is D.

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Detailed Solution

detailed_solution_thumbnail

$V_{max} = Aω$
Average speed = 4A/T

$Average speed = \frac{4 Aω}{2 π} = \frac{2 Aω}{π}$

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