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Q.

Maximum value of n+l+m for the last unpaired electron in an element present in 17th group and 4th period of periodic table:

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a

7

b

6

c

4

d

5

answer is C.

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Detailed Solution

For 17th group and 4th period of periodic table the value of the principal(n),azimuthal(l) and magnetic quantum number (m) is 4,1 and +1.

n=4

l=1

 m=+1

The maximum value of n+l+m for the last unpaired electron in an element is found by the calculation,

=n+l+m =4+1+1 =6

Hence he maximum value of n+l+m is 6.

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